Charging or discharging an RC circuit?
Connect Kirchhoff’s voltage law, initial conditions and the expressions for and , then revisit the derivative.
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How was determined?
Start with q = C and i = . Since C is constant, i = C . During charging, = E(1 − ), whose derivative is (E/τ) . Substituting τ = RC gives = (E/R) .
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I struggle with differentiation.
Revisit the rule: the derivative of is a × . In E , E is constant and a = −1/τ. The derivative is −(E/τ) . First practise with 5 .